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有這樣一個(gè)問(wèn)題,如何按日期累計(jì)值

如下表所示:

   日期                   數(shù)值
2009-02-05          2.4
2009-02-06          2
2009-02-07          5
2009-02-08          3.5
 

要實(shí)現(xiàn)如下結(jié)果:
   日期                    數(shù)值      累計(jì)
2009-02-05          2.4       2.4
2009-02-06          2         4.4
2009-02-07          5         9.4
2009-02-08          3.5       12.9


使用以下sql語(yǔ)句即可實(shí)現(xiàn):
--累計(jì)計(jì)算
select aa.日期,aa.數(shù)值,sum(lj.數(shù)值) as 累計(jì)
from 累計(jì) lj inner join
         (select *
        from 累計(jì)) aa on lj.日期<=aa.日期
where (aa.日期<='2009-02-08') --日期可變?yōu)闀r(shí)間段
group by aa.日期,aa.數(shù)值
order by aa.日期